p^2-8p=21=6

Solution for p^2-8p=21=6 equation:

p^2-8p=21=6

We move all terms to the left:

p^2-8p-(21)=0

a = 1; b = -8; c = -21;
Δ = b2-4ac
Δ = -82-4·1·(-21)
Δ = 148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{148}=\sqrt{4*37}=\sqrt{4}*\sqrt{37}=2\sqrt{37}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{37}}{2*1}=\frac{8-2\sqrt{37}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{37}}{2*1}=\frac{8+2\sqrt{37}}{2}
$